$\sin((n+1)x) \sin((n+2)x)+\cos((n+1)x) \cos((n+2)x)=\cos(x)$
Hi, I have been trying to solve this trigonometric function since last hour but not able to please help me to solve the above trigonometric function.
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Sign up to join this community$\sin((n+1)x) \sin((n+2)x)+\cos((n+1)x) \cos((n+2)x)=\cos(x)$
Hi, I have been trying to solve this trigonometric function since last hour but not able to please help me to solve the above trigonometric function.
We use the subtraction rule for cosines: $$\cos(a-b)=\cos a\cos b+\sin a\sin b.\tag{$1$}$$ Put $a=(n+2)x$ and $b=(n+1)x$. The right-hand side of $(1)$ is then the complicated expression you were given, except yours mentioned the sines first.
So your expression is equal to $\cos\left((n+2)x-(n+1)x\right)$. But $(n+2)x-(n+1)x=x$.