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Prove that if $z_1*z_2=0$ then at least one of $z_1$ and $z_2$ must be 0. $z_1$ and $z_2$ are complex numbers by using the following property: $|z_1z_2|=|z_1||z_2|$

Approach:

if $z_1*z_2=0$ then $$|z_1*z_2|=|0|$$ $$|z_1*z_2|=0$$ $$|z_1||z_2|=0$$

This implies that at least one $z_i$ must be 0 so $|z_i|=0$

How does that look?

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  • $\begingroup$ Have you proved that the only complex number of norm zero is $0$? $\endgroup$ – David P Jul 26 '16 at 0:36
  • $\begingroup$ I know what the norm is but in this case $|z_i|$ is just the distance from the origin the the complex point. I don't know if that is required. $\endgroup$ – TheMathNoob Jul 26 '16 at 0:37
  • $\begingroup$ What about the contrapositive statement. If both $z_1$ and $z_2$ are nonzero, that their product must be nonzero. That should be immediately obviously true. $\endgroup$ – JMoravitz Jul 26 '16 at 0:42
  • $\begingroup$ it reduces to say $\frac{1}{a+ib} = \frac{a-ib}{a^2+b^2}$ $\endgroup$ – reuns Jul 26 '16 at 0:44
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    $\begingroup$ The last sentence of the post went the wrong way. It should be at least one $|z_i|=0$, so $\dots$. $\endgroup$ – André Nicolas Jul 26 '16 at 2:18
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In polar form, $z_1=r_1.e^{i\theta_1}$ and $z_2=r_2.e^{i\theta_2}$.

Then $z_1.z_2=0\implies r_1r_2=0$ as $e^{i(\theta_1+\theta_2)}\ne0$ which suggests $r_1=0$ or $r_2=0$ i.e $\sqrt{a_i^2+b_i^2}=0$ for $i=1$ or $2$$\implies a_i=b_i=0$ for $i=1$ or $2$

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