I'm reading the book 'Trig without tears' by Stan Brown and there is a table mentioning the method for finding the sides of a triangle (not only right triangles) when only the area and 2 angles are given. It wrote
'Find the third angle. Area = ½a b sin C, half of base × height, so substitute b = a×sin B/sin A from the Law of Sines (equation 28) and solve for a = √[2 Area × sin A / sin B sin C]. Then use the Law of Sines twice more to find the other two sides.'
I really can't understand it. Can anyone help me please?? Thanks!!!! :)