The values of your function $f$ at positive integers $n$ correspond to the base-$n$ representations of the prime constant.
Indeed, $f$ is closely related to the characteristic function of the prime numbers. For instance, $f(2)$ evaluates to the prime constant $\rho$, defined as:
$$
\rho =\sum _{{p}}{\frac {1}{2^{p}}}=\sum _{{n=1}}^{\infty }{\frac {\chi _{{{\mathbb {P}}}}(n)}{2^{n}}},
$$
where $\chi_\mathbb{P}$ is the characteristic function of the primes, i.e., the function such that for positive integer $n$:
$$
{\displaystyle \chi_\mathbb{P}(n):={\begin{cases}1&{\text{if }}x\in \mathbb{P},\\0&{\text{if }}x\notin \mathbb{P},\end{cases}}}
$$
where $\mathbb{P}$ denotes the set of prime numbers.
The decimal expansion of $\rho$ begins with:
\begin{align}
\rho&=0.414682509851111660248109622\ldots \\
&=0.011010100010100010_2.
\end{align}
and is included in the OEIS as sequence A051006.
The values of $f$ for other integers $n$ correspond simply to the base-$n$ representations of the prime constant. If we denote by $\rho_n$ the base-$n$ representation of $\rho$, we have:
\begin{align}
f(3)=\sum _{{p}}{\frac {1}{3^{p}}}&=\rho_3 \\
&=0.011010100010100010_3 \\
&=0.152726266\ldots...
\end{align}
Therefore $f(n)=\rho_n$ for positive integers $n$.
f(2)
and compare it to common constants? $\endgroup$ – ypercubeᵀᴹ Jan 13 '17 at 13:01