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I have got a system of non-linear equations of the form

$$A x_1^B \exp \bigg(\frac{- C}{x_1} \bigg) = k_1$$ $$A x_2^B \exp \bigg(\frac{- C}{x_2} \bigg) = k_2$$ $$A x_3^B \exp \bigg(\frac{- C}{x_3} \bigg) = k_3$$

where $[x_1, x_2, x_3]$ and $[k_1, k_2, k_3]$ are known. The couple of constants $[A, B, C]$ is the unknown.

I'd like to know what is the best way to solve this kind of problem involving a non-linear system of equations.

Thanks a lot.

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    $\begingroup$ If you know what the $x_{i}, k_{i}$ are, why not just take logs of both sides of each equation? You'll get a system of three equations in three unknowns which, although it might be messy, should be solvable using the normal linear algebra methods no? $\endgroup$ – Mattos Jun 22 '16 at 13:04
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We have three equations of the form

$$\alpha \, x_i^{\beta} \exp \left(- \frac{\gamma}{x_i}\right) = k_i$$

Taking the logarithm of both sides,

$$\ln (\alpha) \, + \ln (x_i) \beta - \left(\frac{1}{x_i}\right) \gamma = \ln (k_i)$$

Let $\tilde{\alpha} := \ln (\alpha)$. We then obtain a linear system

$$\begin{bmatrix} 1 & \ln (x_1) & -\frac{1}{x_1}\\ 1 & \ln (x_2) & -\frac{1}{x_2}\\ 1 & \ln (x_3) & -\frac{1}{x_3}\end{bmatrix} \begin{bmatrix} \tilde{\alpha}\\ \beta\\ \gamma\end{bmatrix} = \begin{bmatrix} \ln (k_1)\\ \ln (k_2)\\ \ln (k_3)\end{bmatrix}$$

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