Let me first state that I am a category theory novice so your patience is appreciated. I might be making some very basic conceptional mistakes and I might just need a simpler language to do what I want to do (in particular, I seem to get down to the level of relations in objects..).

What I thought I was doing was defining a category as follows.

Take a category $\mathcal{C}_1$ made out of objects which all satisfy the axioms $\mathcal{I}$. Take a particular functor $F$ from $\mathcal{C}_1$ to $\mathcal{C}_2$. The 'image' of $\mathcal{C}_1$ under $F$ contains objects which satisfy "$F(\mathcal{I})$" but $F$ is not necessarily full. (Also there might be objects in $\mathcal{C}_2$ which satisfy "$F(\mathcal{I})$" but are not the image of any object from $\mathcal{C}_1$.

Therefore there would be this subcategory $\mathcal{C}_{F(\mathcal{I})}$ of $\mathcal{C}_2$ with objects defined as those objects satisfying $F(\mathcal{I})$ and morphisms the same as those of $\mathcal{C}_2$.

Is this an established notion or not a part of category theory (perhaps because of the reference to axioms of objects)?

Let me expand on my question by way of an example.

Consider the category $\mathbf{FinGrp}$ of finite groups with morphisms given as homomorphisms and the category $\mathbf{FinAlg_{\mathbb{C}}}$ of finite dimensional complex associative algebras with linear algebra homomorphisms for morphisms.

There is a (covariant) functor $\mathbb{C}:\mathbf{FinGrp}\rightarrow \textbf{FinAlg}_{\mathbb{C}}$ which associates to each group $G$ its group ring $\mathbb{C}G$ and to each group homomorphism $\varphi:G_1\rightarrow G_2$ the linear algebra homomorphism:

$$(\mathbb{C}\varphi):\mathbb{C}G_1\rightarrow \mathbb{C}G_2\,,\,\,\,\delta^g\mapsto \delta^{\varphi(g)}.$$

(is this OK?)

Now if we delve deeper into the objects of the category $\mathbf{FinGrp}$ we see some relations that hold for each object. Let $G$ be a finite group. There is an (associative) multiplication $m:G\times G\rightarrow G$, a unit $e\in G$ as well as an inverse ${}^{-1}:G\rightarrow G$.

The associativity of $m$ can presented as:

$$m\circ (I_G\times m)=m\circ (m\times I_G).$$

Define maps $L_e:G\rightarrow G\times G$ by $g\mapsto (e,g)$ and $R_e:G\rightarrow G\times G$ by $g\mapsto (g,e)$. Then the unit is axiomised as

$$m\circ L_e=I_G=m\circ R_e.$$

Finally inverses. Define $D:G\times G\rightarrow G$ by $g\mapsto (g,g)$ and $\pi_e:G\rightarrow G$ by $g\mapsto e$. Then inverses are axiomised by

$$m\circ({}^{-1}\times I_G)\circ D=\pi_e=m\circ(I_G\times{}^{-1})\circ D.$$

Let us call these three relations/predicates/axioms by $\mathcal{I}_a,\,\mathcal{I}_u$ and $\mathcal{I}_i$.

Does it make any sense or is there a canonical way to talk about the image of (these) predicates under a functor (for example the functor $\mathbb{C})$?

For example, the axioms of the group $G$ can be encoded in $\mathbb{C} G$ in the following way. I don't think this is anyway canonical: how would I describe this 'routine'? Should I just say that the group axioms look like or are translated in this way?

By the natural embedding $\iota:G\hookrightarrow\mathbb{C} G$, $g\mapsto \delta^g$, the group law on $G$ may be extended to a linear multiplication $\mathbb{C} G\otimes\mathbb{C} G\rightarrow \mathbb{C} G$. Start with the group law, a multiplication $m:G\times G\rightarrow G$ defined by $$m(g,h)=g\cdot h.$$ The multiplication on $G$ can be extended to a bilinear mapping $\overline{m}$ on $\mathbb{C} G\times \mathbb{C} G$ and via the universal property to a linear map $$\nabla: \mathbb{C} G\otimes \mathbb{C} G\rightarrow \mathbb{C} G.$$

The vector space $\mathbb{C} G$ together with the multiplication $\nabla$ is a complex associative algebra called the group ring of $G$.

$$\nabla\circ(\nabla\otimes I_{\mathbb{C} G})(\delta^g\otimes \delta ^h\otimes \delta^k)=\nabla\circ(I_{\mathbb{C} G}\otimes\nabla)(\delta^g\otimes \delta ^h\otimes \delta^k).$$ The identity element is encoded via the unit map $$\eta:\mathbb{C}\rightarrow\mathbb{C} G\,,\,\,\,\lambda\mapsto \lambda\delta^e.$$ Note that $\delta^e$ is the unit for the algebra $\mathbb{C} G$.

Note that using the isomorphisms $\mathbb{C}\otimes\mathbb{C} G\cong \mathbb{C}G\cong \mathbb{C} G\otimes \mathbb{C}$: $$\nabla\circ (\eta\otimes I_{\mathbb{C} G})(\lambda\otimes \delta^g)\cong I_{\mathbb{C}G}(\lambda\delta^g)\cong\nabla\circ(I_{\mathbb{C} G}\otimes\eta)(\delta^g\otimes \lambda).$$ To complete this process inverse elements must be considered. The inversion map $G\rightarrow G$, $g\mapsto g^{-1}$ may be extended to $\operatorname{inv}:\mathbb{C} G\rightarrow \mathbb{C} G$. Consider also the maps $\delta^g\mapsto \delta^g\otimes \delta^g$ and $\lambda \delta^g\mapsto \lambda$. Denote these maps by $D$ and $\pi_{\mathbb{C}}$ respectively. Now inverse elements are encoded by: $$\nabla\circ(\operatorname{inv}\otimes I_{\mathbb{C} G})\circ D(\lambda\delta^g)=\eta\circ \pi_{\mathbb{C}}(\lambda \delta^g)=\nabla\circ( I_{\mathbb{C} G}\otimes\operatorname{inv})\circ D(\lambda\delta^g).$$ Note that all of these maps are linear so it suffices to consider their action on basis elements only and so the group axioms are equivalent to the following relations between maps related to $\mathbb{C} G$:

\begin{eqnarray} \nabla\circ(\nabla\otimes I_{\mathbb{C} G})=\nabla\circ(I_{\mathbb{C} G}\otimes\nabla) \\ \nabla\circ(\eta\otimes I_{\mathbb{C} G})\cong I_{\mathbb{C} G}\cong \nabla\circ(I_{\mathbb{C} G}\otimes\eta) \\ \nabla\circ(\operatorname{inv}\otimes I_{\mathbb{C} G})\circ D=\eta\circ\pi_{\mathbb{C}}=\nabla\circ(I_{\mathbb{C} G}\otimes\operatorname{inv})\circ D. \end{eqnarray}

Is there any sense in calling these axioms by $\mathbb{C}(\mathcal{I}_a,\mathcal{I}_u,\mathcal{I}_i)$? Or referring to the subcategory of $\mathbf{FinAlg}_{\mathbb{C}}$ which satisfies $\mathbb{C}(\mathcal{I}_a,\mathcal{I}_u,\mathcal{I}_i)$ by $\mathcal{C}_{\mathbb{C}(\mathcal{I})}$ where $\mathcal{I}$ are these group axioms.

  • 2
    $\begingroup$ I am not sure but I believe you are mixing here some different levels of categorical thinking. In the category of groups the multiplication map $m$ of a group $G$ cannot really be perceived (it is only a morphism of groups if $G$ is abelian), so it is not immediately clear from that point of view how to derive the corresponding maps for the group ring. However you can think of a group to be a set together with maps like multiplication and inversion etc and consider the functor $\mathbb{C}$ from $\mathbf{FinSet}$ to $\mathbf{Vect}_{\mathbb{C}}$ and the axioms on both sides. $\endgroup$ – Matthias Klupsch Jun 20 '16 at 10:50

I interpret your question about group algebras to really be something like the following:

What extra structure do group algebras have that allows you to "remember" that they come from groups, and in particular how do you see the group theory axioms in terms of this structure?

The answer is that group algebras have the additional structure of a Hopf algebra. The map $\text{inv}$ is part of this structure; it is called the antipode. The map $D$ is also part of this structure; it is called the comultiplication. All of the axioms for groups generalize to corresponding axioms for Hopf algebras. Moreover, the functor from groups to Hopf algebras is fully faithful and so restricts to an equivalence of categories.

But an arbitrary algebra doesn't come equipped with any $\text{inv}$ or $D$ maps, so it's unclear what it would mean to impose axioms on such an algebra involving them.

  • $\begingroup$ Actually this work is precisely about Hopf algebras! On the one hand, take out all mentions of category theory and - after composing with the functor from finite algebras to finite coalgebras - the above amounts to a motivation of why we define Hopf algebras as we do. I am wondering is this all I have or is there a genuine categorical language to talk about this? $\endgroup$ – JP McCarthy Jun 21 '16 at 9:05
  • $\begingroup$ I see in the related questions (math.stackexchange.com/questions/179375/…) that the image of a commutative diagram under a functor is a commutative diagram --- Matthias above says that if I want to do it like this then I need to go down to the category of sets. $\endgroup$ – JP McCarthy Jun 21 '16 at 9:07
  • $\begingroup$ By the way (and I appreciate your patience), is it a full functor? What about noncommutative and noncocommutative Hopf algebras? $\endgroup$ – JP McCarthy Jun 21 '16 at 9:08
  • $\begingroup$ Basically I am hoping to motivate the definitions of (finite) quantum groups, random walks on quantum groups and corepresentations... and all can be motivated by taking the relations in the group setting, translating to the algebra setting using this $\mathbb{C}$-functor and then 'dualising' into the category of finite coalgebras. $\endgroup$ – JP McCarthy Jun 21 '16 at 9:10
  • $\begingroup$ @Jp: you can think of cocommutative Hopf algebras as group objects in cocommutative coalgebras (and $X \mapsto \mathbb{C}[X]$ as a fully faithful embedding of sets into cocommutative coalgebras), and dually you can think of commutative Hopf algebras as group objects in affine schemes (affine group schemes). These are both very natural definitions to write down. From here it's not hard to wonder what happens if you drop both commutativity and cocommutativity. $\endgroup$ – Qiaochu Yuan Jun 21 '16 at 17:58

This answers my question and follows on from the comments of Matthias on this subsequent question.

Is this an established notion or not a part of category theory (perhaps because of the reference to axioms of objects)?

If the axiom is a commutative diagram (expressing a relation between objects and morphisms) in a category $\mathcal{C}_1$ then yes. The image of a commutative diagram under a functor $F:\mathcal{C}_1\rightarrow \mathcal{C}_2$ is another commutative diagram, this time expressing a relation between objects and morphisms in the category $\mathcal{C}_2$.

Does it make any sense or is there a canonical way to talk about the image of (these) predicates under a functor (for example the functor $\mathbb{C})$?

No. They need to be about objects and morphisms for the functor to 'see' them.

Is there any sense in calling these axioms by $\mathbb{C}(\mathcal{I}_a,\mathcal{I}_u,\mathcal{I}_i)$? Or referring to the subcategory of $\mathbf{FinAlg}_{\mathbb{C}}$ which satisfies $\mathbb{C}(\mathcal{I}_a,\mathcal{I}_u,\mathcal{I}_i)$ by $\mathcal{C}_{\mathbb{C}(\mathcal{I})}$ where $\mathcal{I}$ are these group axioms.

See this answer.


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.