13
$\begingroup$

I just read that disjoint events, A, B, if, $\mathbb{P}(AB) = 0$ are independent. This really frustrates me.

My teacher stated otherwise - $\mathbb{P}(AB) = 0 \iff A \cap B = \emptyset \implies \mathbb{P}(AB) = 0 \ne \mathbb{P}(A)\mathbb{P}(B)$ because $\mathbb{P}(A)$ and $\mathbb{P}(B)$ are not empty (does the latter come from the definition of independent events?).

Could somebody clear this for me?

$\endgroup$
2
  • $\begingroup$ Please read the tags carefully. Do not use the self-learning tag because you are studying the material by yourself/alone. $\endgroup$ – Em. Jun 20 '16 at 0:50
  • 4
    $\begingroup$ Where did you read that disjoint events are independent? $\endgroup$ – bof Jun 20 '16 at 2:18
18
$\begingroup$

You are correct, and your reasoning is spot on. Disjoint events aren't independent, unless one event is impossible, which makes the two events trivially independent. Let's take the simplest situation possible as a counterexample. Let $A$ be the event that a fair coin lands heads and let $B$ be the event that the coin lands tails. $A \cap B = \emptyset \implies P(A \cap B) = 0 \ne P(A)P(B) = \frac{1}{2}\cdot \frac{1}{2}.$ The mathematical definition of two events being independent is $P(A \cap B)=P(A)\cdot P(B)$ thus if $A \cap B = \emptyset$ then $P(A \cap B) = 0 \implies P(A) = 0$ or $P(B) = 0$

$\endgroup$
0
7
$\begingroup$

Two disjoint events can never be independent, except in the case that one of the events is null. Essentially these two concepts belong to two different dimensions and cannot be compared or equaled.
Events are considered disjoint if they never occur at the same time. For example, being a freshman and being a sophomore would be considered disjoint events.
Independent events are unrelated events. For example, being a woman and being born in September are (roughly) independent events.

$\endgroup$
1
  • 2
    $\begingroup$ "For example, being a woman and being a freshman are independent events." In which country is that even close to be true? $\endgroup$ – Did Jun 20 '16 at 8:49
1
$\begingroup$

The intersection of two events, $A$ and $B$, is usually represented as $A \cap B$, but sometimes as $AB$ .

Two events are (pairwise) independent if and only if the probability of their intersection equals the product of their probabilities.   It means knowledge of the occurrence of one event does not influence the measure of the (conditional) probability of the occurrence of the other. $$A\perp B ~\iff~ \mathsf P(A\,B)=\mathsf P(A)\,\mathsf P(B)\tag{1}$$

Two events are disjoint, or exclusive, if their intersection is an empty set, which in turn infers it to have zero probability.   The intersection of disjoint events is impossible.   It means the occurrence of one event prohibits the occurrence of the other. $$A\,B=\emptyset ~\implies~ \mathsf P(A\,B)=0\tag{2}$$

These two situations do not occur together, except in the edge case of at least one of the events itself being impossible.   (An impossible event is independent of any other event.)

$\endgroup$

Not the answer you're looking for? Browse other questions tagged or ask your own question.