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I need your help with this question:

The tangent line to the function f(x) at x=1 is y=3x-2. Find f(x) (without using integrals).

I know that the derivative at x=1 should be 3, but without more information, how am I suppose to find f(x) ? This is a multiple answers question, but at least 3 answers gives a derivative of 3 when putting x=1.

Thank you.

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  • $\begingroup$ You need $f'(1)=3$, but also $f(1)=1$. $\endgroup$ – Yves Daoust Jun 17 '16 at 13:05
  • $\begingroup$ Obviously many functions satisfy $f(1)=1),f'(1)=3$. What are the alternatives given? $\endgroup$ – almagest Jun 17 '16 at 13:06
  • $\begingroup$ The question seems poorly written; the correct answer should be "there is no way to know." If indeed they want you to pick the function that satisfies $f(1)=1$ and $f'(1)=3$, then they should have written, "Which of the following functions could be a candidate for $f(x)$?" $\endgroup$ – Théophile Jun 17 '16 at 13:09
  • $\begingroup$ I agree with you ! $\endgroup$ – user3275222 Jun 17 '16 at 13:13
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You can't find $f(x)$ because you aren't given enough information. There are many functions that share the same tangent line at a given point.

But you can find $f(1)$ because $f(1)=\ell(1)$, where $\ell$ is the function whose graph is the given tangent line (i.e., $\ell(x)=3x-2$). That's because the tangent at $x=1$ passes through the point $(1,f(1))$.

EDIT: Sorry, I didn't see that you actually do have more information that you aren't telling us.

Note that you really have both $f'(1)=\ell'(1)=3$ and $f(1)=\ell(1)=1$. You may be able to eliminate all but one of the possible answers with this.

Can you also please give us the actual answers you have to choose from?

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    $\begingroup$ But he has enough info. It is a multiple choice question. He just hasn't given it to us yet, so this is premature! $\endgroup$ – almagest Jun 17 '16 at 13:07
  • $\begingroup$ @almagest: Ah, you are right. I didn't read the entire question. My bad. I edited my answer. $\endgroup$ – MPW Jun 17 '16 at 13:08
  • $\begingroup$ Can e^(3*(x-1)) be the correct answer? $\endgroup$ – user3275222 Jun 17 '16 at 13:11
  • $\begingroup$ @user3275222: If $f(x)=e^{3(x-1)}$, then $f(1)=e^0=1$, and $f'(1)=3e^0=3$. So yes, that is a possible candidate. $\endgroup$ – MPW Jun 17 '16 at 13:13
  • $\begingroup$ Thanks, problem solved (and sorry for not writing the expression properly, not controlling latex yet). $\endgroup$ – user3275222 Jun 17 '16 at 13:17

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