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This question already has an answer here:

Maybe this question is too dumb to be asked, but it's really bugging me so I decide to ask it anyway. I hope you bear with me.

Okay, it's known that both sides of the following series equal.

$$\pi=4\sum_{n=0}^{\infty}\frac{(-1)^n}{2n+1}\tag1$$

and

$$e=\sum_{n=0}^{\infty}\frac{1}{n!}\tag2$$

We all agree at this point. Now, each terms in $(1)$ and $(2)$ is a rational number. We all agree without a doubt. The sum of rational numbers is always a rational number. We agree again. Hence it follows that $\pi$ and $e$ must be rational numbers. However, it contradicts the well-known facts that both $\pi$ and $e$ are irrational numbers. So, where is my mistake?

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marked as duplicate by Dietrich Burde, Watson, Michael Hoppe, Dan Rust, Claude Leibovici calculus Jun 17 '16 at 10:29

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

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    $\begingroup$ "The finite sum of rational numbers is always a rational number" $\endgroup$ – Kevin Quirin Jun 17 '16 at 9:08
  • $\begingroup$ This, as commented above, is one of the most important and sharp difference between finite and infinite in these matters: infinite (converging, of course) sums of rationals don't necessarily are rationals $\endgroup$ – DonAntonio Jun 17 '16 at 9:14
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    $\begingroup$ See also this question. $\endgroup$ – Dietrich Burde Jun 17 '16 at 9:16
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    $\begingroup$ Perhaps $\sqrt{2} = \dfrac{1}{1}+\dfrac{4}{10}+\dfrac{1}{100}+\dfrac{2}{1000}+\cdots$ as simpler counterexample $\endgroup$ – Henry Jun 17 '16 at 9:17
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An "infinite sum" is not a sum.

An infinite sum is the limit of a sequence :

$$\sum_{n=0}^\infty=\lim_{N\to\infty} \sum_{n=0}^N.$$

An the limit of a sequence of rational numbers is not necessarily rational.

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    $\begingroup$ This is as simple, short and accurate as possibly expected (by me, at least). Very nice. +1 $\endgroup$ – DonAntonio Jun 17 '16 at 9:21
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Take any known irrational number, $x$. You can always represent $x$ by the sum of an infinite number of rational numbers.

For example, take the decimal representation of $x$:

$x = 5.1938527\ldots$

and then each term in the sum could form one of the decimal digits:

$x =5 + \frac{1}{10} + \frac{9}{100} + \frac{3}{1000} + \cdots$

Therefore the sum of an infinite number of rationals is not always rational.

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