I originally understood limits to be where functions run towards $\pm\infty$ as they approach some specific $x$ value and where they run towards (but never touch) some specific value (like $0$) as $x$ approaches infinity, thus making that value impossible to reach (a limit a function can't cross, in a Zeno's paradox-like way).

Now that I'm beginning to actually study calculus, I'm seeing that limits are somehow more broad. Specifically, I now see limits are always referred to in relation to some stated $x$ value being approached (as indicated by the conventional notation: $\lim_{x\to p} f(x)$). But, this makes it seem to me like you can pick any value (any $p$) you want, that the limit is simply whatever value the function approaches as $x$ approaches whatever value you decided to pick.

    • Wouldn't that mean functions have an infinite number of limits? (You can find an infinite number of points on a line/curve, after all.)
    • If so, what's so limiting about "limits" then?
    • Also, wouldn't this make limits the most stupidly obvious things? For example: $f(x)=x^2$ will obviously approach $4$ as you pick $x$ values arbitrarily closer and closer to $2$ ($1.9, 1.99. 1.999, 1.9999, 1.99999,$ etc)?
  1. If functions don't have an infinite number of limits, than how do you recognize which values for $x$ to approach make sense?

Obviously, preconceived notions can screw with actually learning how a thing works because it can frame the information you're trying to integrate within a meaningless perspective, but figuring out how to shed those preconceived notions can be hard when you don't understand where you've gone wrong in the first place. ...oh, god, someone help me. I'm stuck in a loop.

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    $\begingroup$ Well a completely discontinuous function wouldn't have an infinite number of limits (I assume such a function exists). Otherwise, if any function has an interval of non-zero length which is continuous then yes, there are an infinite number of "limit points" (on that interval). In a sense, all limits are "obvious" (since they exist). But usually it's when algebraic limits do not immediately appear to exist that they are "interesting" such as derivatives: $\lim_{h \rightarrow 0} \frac{f(x + h) - f(x)}{h}$. That limit is very curious and sometimes exists and sometimes doesn't. $\endgroup$
    – Jared
    Commented Jun 9, 2016 at 6:06
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    $\begingroup$ You may want to read up on the epsilon-delta definition of a limit. It'll seem somewhat cryptic at first glance, but once you know precisely what a limit is, everything will be clear to you. $\endgroup$ Commented Jun 9, 2016 at 6:08
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    $\begingroup$ Seriously, silly questions are the ones that are most worth asking. They indicate that you are getting at the meaning of something and not just memorising a nice-sounding phrase or a magic spell. Half the advances of mathematics come from silly questions: what if $ab\ne ba$? $\sqrt{-1}$ doesn't exist, so what is its value? (Same question for $-1$, for that matter) what is the infinite sum $1+2+3+4+5+…$? (Euler says $-1$). $\endgroup$ Commented Jun 9, 2016 at 6:36
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    $\begingroup$ (Sorry, that should have been $1+2+4+8+16…=-1$) $\endgroup$ Commented Jun 9, 2016 at 7:21
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    $\begingroup$ The definition of "limit" that you initially talk about (getting closer and closer to a value, but never reaching it) sounds pretty close to the definition of an asymptote. $\endgroup$
    – psmears
    Commented Jun 9, 2016 at 13:24

6 Answers 6


First, congratulations on being an inquisitive mathematics student! These sorts of questions are one of the most important questions you should be asking yourself and others. Questions such as "why is this important?" and "why is this called that way?" are precisely what mathematics is about - i.e. it's not a set of arbitrary rules to annoy students, all the things got created for a reason!

Are there infinitely many boring limits?

You are correct, most "nice" functions defined on an interval or on $\mathbb R$ have infinitely many limits (see the comments section for counterexamples) and yes, they are "stupidly obvious" for continuous functions, i.e. $$\lim_{x\to a} f(x) = f(a)$$ which is often the definition of continuity, too.

But then there are many interesting cases, for example, try to figure out what's happening for $\lim_{x\to 0} \sin(1/x)$ and $\lim_{x\to 0} x\sin(1/x)$. Even if this is beyond your level, just thinking about the functions and looking at their graphs will give you some intuition about how interesting limits can be. One of them is continuous at zero. Which one? Why? What happens to the other one?

$$\sin(1/x)$$ <span class=$\sin(1/x)$" /> $$x\sin(1/x)$$ $x\sin(1/x)

As a sidenote, there are also functions that are discontinuous everywhere. Those are usually rather hard to understand, though (althought Dirichlet's function is quite accessible)

Even "boring" limits are useful

But even for functions that are not that interesting, like $\text{sgn}(x)$, which gives you the sign $x$, i.e. it is $-1$ for negative numbers, $1$ for positive numbers and $0$ for zero, limits are a useful concept. The one-sided limits at zero (coming from left and right) are $-1$ and $1$, respectivelly, whereas the function value is $0$. This intuitively makes complete sense (draw it!) and thus having a rigorous mathematical object, the limit, to support this intuition is useful.

Why "limit"?

I do not know the proper etymology of the mathematical term "limit", but the english word comes from the word for "frontier", or "boundary". This makes sense even for a "boring" limit, like $\lim_{x\to 2} x^2$ - as you yourself suggested, you can approach it through the sequence $1.9,1.99,1.999,\dots$, that is you are coming closer and closer to the boundary point $2$, but never quite touch it, even though you're performing infinitely many steps. In that sense, $2$ would be your "limit", or the "boundary", which you never quite attain.

Lastly, note that you never actually touch the limit point while you're approaching the limit. This is important - what if the point was, say, undefined! Answers by other users stress this point more, make sure you read them.

  • $\begingroup$ Isn't it: "All functions defined on an infinite set have zero or infinite limits?" If one were to divide the indicator function of natural numbers by itself, wouldn't that yield a function that is defined on an infinite set, yet does not have infinitely many limits? (As it has none) $\endgroup$ Commented Jun 9, 2016 at 11:30
  • $\begingroup$ Right, it does appear my statement is wrong. I am leaning towards editing my answer to simply leave out the "infinite set" bit and just keep "$\mathbb R$ or an interval", as I don't believe such discussion is very relevant to the OP's question, but for (mostly my) clarity: isn't that then a function defined on $\mathbb N$ which has no limit points, in which case I'm not even sure what the definition of a limit would be? $\endgroup$
    – Dahn
    Commented Jun 9, 2016 at 11:43
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    $\begingroup$ 0 on rationals / 1 on irrationals has no limits anywhere $\endgroup$
    – djechlin
    Commented Jun 9, 2016 at 14:04
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    $\begingroup$ A constant function only has one limit. $\endgroup$ Commented Jun 9, 2016 at 15:07
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    $\begingroup$ @DanielR.Collins No, a constant function has a limit at every point in it's domain -- it's just that the value of that limit is always the same. It's like saying "every child in this family has the same mother" being different from "only one child in this family has a mother". A function that had only one limit seems impossible. $\endgroup$ Commented Jun 9, 2016 at 15:22

For typically used functions at typically considered values, limits and evaluation are the same thing.

More precisely, "typical" functions are continuous at "typical" values, and we have a theorem (or definition)

If $f$ is continuous at $a$, then $\lim_{x \to a} f(x) = f(a) $

Limits generalize this notion; e.g. if I define a function $f$ that is undefined at $x=1$ but satisfies $f(x) = x+1$ whenever $x \neq 1$, then the graph looks like

line with a hole in it

The hole is easily filled in to make a continuous graph; the limit is a systematic way to determine precisely what value is needed to fill in the gap: here,

$$ \lim_{x \to 1} f(x) = 2 $$

We could then define a function $\bar{f}$ that is a continuous extension of $f$ by filling in the hole:

$$ \bar{f}(x) = \begin{cases} f(x) & x \neq 1 \\ 2 & x = 1 \end{cases} $$

then limits are once again just evaluation: e.g.

$$ \lim_{x \to 1} \bar{f}(x) = \bar{f}(1) $$

Incidentally, a sample formula for the function $f$ is

$$ f(x) = \frac{x^2-1}{x-1} = \frac{(x-1)(x+1)}{x-1} $$

and a formula for the continuous extension is

$$\bar{f}(x) = x+1 $$

The same is true for limits at infinity; an important concept in analysis often not taught in introductory classes is the extended number line whose points are called extended real numbers. It is formed by adding two new points $+\infty$ and $-\infty$ at the 'ends' of the ordinary number line.

There is a topological definition of limit that can be applied for functions on the extended number line or that take values in the extended real numbers (or both); the notion of limit is once again that of filling in holes. And again we are interested in doing continuous extensions; e.g. to define $\arctan(+\infty) = \pi/2$ and $\arctan(-\infty) = -\pi/2$.

The "filling in holes" idea can be made precise using topology — in particular, in terms of the closure of the graph of a function.


I think you have the notion that limits are useful to study behavior of a function at some troublesome points like say the behavior of $f(x) = 1/x$ at the troublesome point $0$. This is a good start and mathematicians actually carried the idea a bit far and limits are used to study behavior of function not only at troublesome points but also at normal points where there is no trouble.

More specifically when we are dealing with limit of a $f$ at a point $c$ then we are not at all interested in the question "What is the value of $f$ at $c$?" but we are rather interested in studying the values of $f$ at all points near to $c$. Thus as long as a function $f$ is defined at all points near $c$ it is OK to talk about its limit at $c$. Hence depending upon the function it is possible to talk about its limit at many points. Thus for example if $f(x) = x^{2}$ then we can talk about its limit at any point $c$ without any problem. Thus to use your phrase "functions can have an infinite number of limits".

Now you ask: what is limiting about limits? I think the "limiting part" comes from the fact that the limit of $f$ at $c$ is dependent on values of $f$ at all points near $c$ but not dependent at all on its value at $c$. This is sometimes expressed by the fact that the values of the variable (say $x$) which we are dealing with are limited (or say restricted) so as not to reach point $c$. On the other hand some students mistakenly think that if $\lim_{x \to c}f(x) = L$ then $f(x)$ cannot reach $L$. This is wrong (just take any function $f$ which is constant). The limiting part is related to the variable $x$ and not to the values of function $f(x)$. However there can be cases where $f(x)$ is also restricted not to reach its limit $L$ but it is not necessary to be so.

Wouldn't this make limits the most stupidly obvious thing? You are now talking about functions $f$ and points $c$ such that $f$ has no troublesome behavior near $c$. Technically we say in this case that $f$ is continuous at $c$ and $\lim_{x \to c}f(x) = f(c)$. There are many functions whose limit at a point is same as their value at that point. Then why bother to study the limit of such functions? Well such functions possess many nice properties which are not too difficult but perhaps may not be obvious.

For example let $f$ be a function which is continuous at $c$ (think $f(x) = x^{2}$ at $x = 2$) and also assume that $f(c) > 0$. Then it can be observed with a little effort that $f$ is positive at all points near $c$. If $f(c) < 0$ then $f$ would be negative at all points near $c$. Thus continuous functions preserve signs near the point of continuity. Now consider that the function $f$ is continuous at all points of an interval $[a, b]$. Then the magic happens and it is difficult to prove that if $f(x) \neq 0$ for all $x \in [a, b]$ then $f$ maintains a constant sign on whole interval $[a, b]$. The fact mentioned in the last sentence is not obvious and may not hold for discontinuous functions. There are many further properties of continuous functions which emphasize the need to study such studpidly obvious limits.

Continuous functions ensure that their values change only slightly when their argument changes slightly. Thus there are no surprises. On the other hand consider the function $f(x) = 1/x$ near $0$. If $x$ is positive and near $0$ (say $x = 0.00001$) then $f$ has a large positive value. Change the value of $x$ by a little amount to make $x = -0.00001$ and then value of $f$ is suddenly a big negative number. This kind of small change in value of $x$ leads to a very big change in value of $f$ and this is more of a trouble / surprise for us (think of stories of a king becoming a pauper the next day, who would want that!). So continuity is a desirable property and it is worth studying.

Lastly you ask: how do you recognize which values for $x$ to approach make sense? The answer is simple. We can talk about $\lim_{x \to c}f(x)$ provided the function $f$ is defined in a certain neighborhood of $c$ (except possibly at $c$). The the points $c$ for which it makes sense for $x$ to approach are those specific points near which the function is defined.

It is better to give examples. Let $f(x) = 1/x$. Then although $0$ is a troublesome point (because $f$ is not defined there), it makes sense to see what happens when $x$ approaches $0$. It makes sense because apart from $0$ $f$ is defined at all nearby points. And $0$ is the only troublesome point, and rest of the points are fine and for this function it also makes sense to see what happens when $x$ approaches a non-zero point.

Now consider $f(x) = 1/\sin(1/x)$. Here the function is defined at all points except $ x = 1/n\pi$ and you can see that it makes sense to see what happens when $x$ approaches $1/n\pi$. But it does not make sense to see what happens when $x$ approaches $0$ because every neighborhood of $0$ contains these exceptional points $x = 1/n\pi$ where $f$ is not defined. So for this function we can't talk about $\lim_{x \to 0}f(x)$.

  • $\begingroup$ For the last paragraph: it depends on the definition of limit. I was taught that you can consider limit of a function in every limit point of its domain. Then there are sequences in the domain convergent to the limit point, so you can examine limits of sequences of values for those sequences. $\endgroup$
    – eudes
    Commented Jun 9, 2016 at 22:06
  • $\begingroup$ There is more simple reason $\lim_{x \to 0} f(x)$ doesn't exist (in your last paragraph)---$f$ is unbounded both above and below about every neighbourhood of $0$. $\endgroup$ Commented Jun 10, 2016 at 0:27
  • $\begingroup$ @eudes: yes you are right. I was trying to use the simpler definition suitable for beginners who are not aware of terms like limit points, open and closed sets and other related terms. $\endgroup$
    – Paramanand Singh
    Commented Jun 10, 2016 at 2:18
  • $\begingroup$ @MathematicsStudent1122: I am not saying that $\lim_{x\to 0}f(x)$ doesn't exist, but rather that we can't talk about the limit of $f$ at $0$. I have given another example of $1/x$ and then we can talk about its limit at $0$. $\endgroup$
    – Paramanand Singh
    Commented Jun 10, 2016 at 2:24
  • $\begingroup$ @ParamanandSingh You're right about that. However, what definition of the limit are you using? Rather than considering the neighbourhood, why not $\text{dom} \ f \ \cap \ (c-\delta, c + \delta)$ (in this case, $c=0$). This has been discussed before, on another question, but there was disagreement, I believe. I fairly certain this is the standard definition has this proviso. $\endgroup$ Commented Jun 10, 2016 at 2:48

Aren't Limits Stupidly Obvious?

To add on to Dahn Jahn's answer, limits seem obvious now but before they weren't. Going back to you saying you are learning calculus, calculus was invented before limits existed, they were only implied. In the 17th century, when Newton and Leibniz was developing modern calculus, they were working with the idea of infinitesimals. They dealt with what could considered to be very, very small numbers. For very obvious reasons, it wasn't very rigorous or well defined. Later, in the 19th century, the concept of limits was explored and the epsilon-delta definition came about. This help to make calculus more rigorous and extend limits to other fields of mathematics.

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    $\begingroup$ I don't think it is correct to say that limits didn't exist when calculus was invented. Cauchy's $\epsilon-\delta$ definition of the limit didn't exist, but the concept was there. Newton and Liebnitz were both aware of the concept. They just didn't have a solid definition to work with. Though Eudoxus gave a viable approach to them nearly 2000 years earlier. That approach was used by Archimedes in particular to prove many limiting results, including the area of a circle and volume of a sphere. $\endgroup$ Commented Jun 9, 2016 at 18:08
  • $\begingroup$ The area of a unit circle. $\endgroup$
    – user301988
    Commented Jun 10, 2016 at 2:26

Dahn Jahn's answer sums it up very well. I would in addition to that stress that limits describe the behaviour of a function close to a value in the range but not at the value itself. If you take a function $g(x) = x^2$ everywhere except that $g(2) = 5$. what is the limit of that function as $x$ gets closer and closer to 2?

Okay that it looks like we have have gone out of our way to make $x = 2$ interesting for $g$ when for $f$ it is not so but it highlights the central reason for considering limits at all.

It is exactly because limits are not concerned with the value of the function at the limiting point that they are so interesting when the function isn't well defined at the limit or something different is happening at that point as in the case above (a discontinuity at $x = 2$).

Most often a limit is useful/interesting because there is something in the expression of the function that is trying to get you to divide by zero which is not allowed and early calculus was beset with arguments about this. Division of a non-zero number by zero is a question - it asks which number when multiplied by zero gives 1? No number does this. Division of zero by zero is just as problematic - which number when multiplied by zero gives zero? All of them.

Calculus was primarily a method of looking at dividing smaller and smaller numbers by other smaller and smaller numbers and seeing what happened and the limit was a way of formalizing this so that the actual division by zero never occurred.

In the same way the notion of the value of a function "at infinity" is not especially well defined - only as a shorthand for something else. Indeed not all limits taken to infinity display the sort of limiting behaviour you describe above. Consider for example the function $h(x) = 2$. The limit of this function as x tends to $\infty$ is 2 and every value in the sequence that you generate to find the limit is also 2. This is simple example of a function that attains its limit even when taking a limit to infinity. It is also a function that does not 'approach' its limit - it gets no closer to 2 than at $x = 0$

The limit of a function as $x$ tends to infinity can be expressed (loosely) as a question: "if I increase $x$ without bound does my function also increase without bound, does it oscillate or does it get as close as I like (and forever stay that close) to some real number?" and that is the essence in the notion of a limit to infinity.

The limit of a function as $x$ tends to some finite value $p$ can be expressed as a similar question: "if I get $x$ closer to $p$ (without reaching $p$) does my function also increase or decrease without bound, does it oscillate or does it get as close as I like (and forever stay that close) to some real number" and that is the essence in the notion of a taking a limit to a finite point. The only caveat is that you can approach a finite point from above and below and if the two approaches do not give you the same value then the limit is not defined.

Admittedly all of this machinery developed to cope with the interesting (problematic) cases works at other points as well even though many limits do turn out to be obvious. You have done nothing wrong by saying what is true: most limits tell you very little of interest or at least very little you didn't already know - but the ones that are interesting are often really very interesting.


Interesting question. If we have a function with a finite number of points, then it's actually impossible for that function to have infinitely many limits (or more precisely limit points), but I assume you don't want to restrict the domain beyond what must be done due to undefined values. Let's start with the definition of a limit.

epsilon: ε, delta: δ

These are used as positive variables in the definition of a limit, you could replace them with more familiar letters if doing so will make it clearer for you.

When we say the limit of f(x) as x approaches c is L, the definition is:

For every ε>0, there exists some value δ>0 such that if |x-c|<δ, then |f(x)-L|<ε

What this means to us is that if you pick any positive value for ε, no matter how close to 0, I can find a positive value for δ that guarantees that as long as x is within a "δ neighborhood" of c (that is, the distance between x and c is less than δ) then f(x) will be within an "ε neighborhood" of L.

Now if you allow for piecewise functions (keeping in mind that even the absolute value function is a piecewise function) then you can define a function f(x) so that f(x)= 0 for rational values of x and f(x)=x for irrational values, this function only has a limit as x approaches 0 (going back to the discussion of ε neighborhoods), and nowhere else.

Someone also mentioned the Dirichlet function, which is a nice example to use. See http://mathworld.wolfram.com/DirichletFunction.html


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