0
$\begingroup$

I'm sorry for the terrible formatting, I'm sorta new so I don't know how to use MathJax very well :( see below for my first attempt :)

I came across the indical expression : $$\frac{x-1}{x-x^{1/2}-2}$$

When I first saw this expression I thought this was the final answer, however it apparently can be simplified to: $$\frac{x^{1/2}-1}{x^{1/2}-2}$$

However I struggle so see how the factorization in this equation is done as my various attempts have resulted in more complicated or wrong expressions. However I have substituted values and the answer is right. If you could please explain the factorization/steps required I would be very thankful :)

$\endgroup$
2
  • 1
    $\begingroup$ Substitute $x=t^2$ and it should fall out. $\endgroup$
    – Lubin
    Jun 5, 2016 at 3:44
  • $\begingroup$ omg thank you so much,( sorry for the extremly late reply ) $\endgroup$
    – John Hon
    Sep 13, 2016 at 13:45

1 Answer 1

0
$\begingroup$

I wish to help out the community by making it clear that this question has been answered by the commentor Lubin where the trick was to "Substitute x=t^2 and it should fall out".

Thank you Lubin :)

$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .