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Let$\lim\limits_{x\to -3} f(x) =2$ and $\lim\limits_{x\to -3} g(x) =9$

Find $\lim\limits_{x\to -3} [\frac{[f(x)]^2}{2+g(x)}]$

I believe that the answer is $4/11$ but I wanted to check with you guys if I did it correctly. I plugged in the $2$ and the $9$ and essentially solved using basic math. Thanks for any helpful tips or advice!

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    $\begingroup$ Yes, you are correct. Limits can be exchanged with multiplication, division, addition, etc (in other words, the limit of a product is the product of the limits, and so on). $\endgroup$ – florence Jun 3 '16 at 1:31
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The answer to this question is just 4/11 as you simply plug in the values and solve as a simple math equation.

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The answer is indeed $4/11$:

$\dfrac{2^2}{2+9} = \frac{4}{11}$

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