How many $3$ digit different number that will be divisible by $5$ can be formed from the digit $0,2,3,4,5,6$ lying between $100$ and $1000$.
Divisible by $5$ is possible only when unit digit will be either $0$ or $5$, means possibility for unit digit is $2$.
And possible number of choices for third place digit is $5$ (except $0$).
And possible number of choices for tenth place digit is $6$ (all).
So, total possible such numbers are $=5\times6\times2=60$ (answer).
Can you explain in formal/alternative way, please?