52% of people want to ban smoking.
Use the normal approximation to estimate that more than half of a given sample size $n$ support the the ban.
For $n=11, 101, 1001$
Are these steps correct:
1.) Finding the mean (p*n)
2.) multiplying by q (pnq), and taking the square root $\sqrt(pqn)$ to find std. dev.
3.)Now we want P(X$\ge$5.5) (5.5 is half or more of our sample size) and we need to subtract 0.5 I believe?
Assuming these steps are correct, what's next?