Combination - How many different ways I am stomped on the following question


How many different ways are there to draw $6$ cards from a standard deck of cards and obtain $4$ kings and $2$ jacks? (The Answer is $6$)


I believe I am starting the question all wrong since I am doing this for


How many different ways are there to draw $6$ cards from a standard deck of cards


No. of ways = $\frac{52!}{46!6!} $
Any suggestions on how I would solve this problem ?
 A: I believe the total number of hands is completely irrelevant for answering this question. All you need to know is that you need 6 cards. 4 cards need to be kings. 4 cards need to be jacks. You only have 4 kings, and you only have 4 jacks. The number of ways you can draw 4 kings out of a set of 4 kings is 4C4 = 1. The number of ways you can draw 2 jacks from a set of 4 is 4C2 = 6. 
This makes your answer 4C4 * 4C2 = 1 * 6 = 6
A: There is only $1$ way to select the kings. There are $\binom{4}{2}$ ways to select $2$ Jacks from the $4$ available.
Or else, in desperation, one can make an explicit list and count: (J$\spadesuit$ J$\heartsuit$); (J$\spadesuit$, J$\diamondsuit$); (J$\spadesuit$, J$\clubsuit$; (J$\heartsuit$, $J\diamondsuit$); (J$\heartsuit$, J$\clubsuit$); (J$\diamondsuit$, J$\clubsuit$).
Remark: As pointed out by jak, in order to prepare for more complicated problems, it may be better to say that there are $\binom{4}{4}$ ways to select the Kings, and for each of these ways there are $\binom{4}{2}$ to choose the Jacks, for a total of $\binom{4}{4}\binom{4}{2}$.
