There is this exercise and for the first time in my life, I don't want to go to see the solution. Instead, I'm more asking of a tiny help to see if I'm right in my conclusion
Kids are getting concerned about this math fascination and I said to them it is for their good...
Humor aside, let's crack on. This is my equation below:
$$ \sin 2x \tan x = 1 - \cos( 2x)$$
$RHS$ is equal to $1- (2\cos^2x-1)$
So I started $LHS$ and eventually, I found this below
I'm not good in maths as many of you but intuitively, I can yet feel that my solution is equivalent to the $RHS$ I mentioned above. However, something is missing to me but I cannot say where...
$$(2-2\cos^2x) \equiv 1- (2\cos^2x-1)$$
Thanks again for your patience in bearing with me