$\neg ((P\land Q)\lor \neg (P\land T)\lor (Q\land T)) \equiv P \land \lnot Q \land T$
Using only De Morgans Laws and the Distribution Laws. I managed to get the left hand side to reduce to the form:
$(\lnot Q \lor \lnot P) \land (\lnot Q \lor \lnot T) \land P \land T$
I'm sure I'm missing an obvious step. Can someone point me in the right direction?