I'm trying to solve this problem:
Find the equation of the tangent to the parabola $y=x^2$.
If the x-intercept of the tangent is 2.
All what I can think of is finding the slope which is
$dy/dx = 2x$
so the tangent line equation would be
$y-y_0 = 2x(x-x_0)$
I don't know exactly where to go from here, should I plug in intercept points?
$y-0 = 2x(x-2)$