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"Boltzmann's equation relates the entropy S of an ideal gas to the number W of microstates corresponding to a given macrostate, via the equation

S = k ln W

where k is the so-called Boltzmann constant. Rearrange this formula to make W the subject"

S = k ln W
S/k = ln W
W = e^S/k

Is this correct? Thanks!

p.s how do i get the exponent to format without the ^ ? And can i write a log, eg. log 5, with the base 5 (or whatever number, e, etc) formatted correctly? I'm new around here..

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  • $\begingroup$ $W=e^{S/k}$ $\log_5(x)$ etc. Where is your mathematical question? $\endgroup$
    – Did
    Commented May 9, 2016 at 10:58
  • $\begingroup$ Did you go through the tour of the session. $\endgroup$ Commented May 9, 2016 at 11:06
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    $\begingroup$ meta.math.stackexchange.com/questions/5020/… Check this out... $\endgroup$ Commented May 9, 2016 at 11:15
  • $\begingroup$ "Rearrange this formula to make W the subject" I'm asking if the formula has be rearranged correctly to make W the subject. $\endgroup$
    – Zantheor
    Commented May 9, 2016 at 11:16
  • $\begingroup$ On the Help page, click on "How do I format mathematics here"? ....and on subsequent links.... Your Answer is correct, provided that $ k \ne 0.$ In physics, zero entropy would require a universe with at most 1 particle or a universe of age 0. $\endgroup$ Commented May 9, 2016 at 13:26

1 Answer 1

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$$W=e^\frac{S}{k}$$

$W=e^\frac{S}{k}$

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  • $\begingroup$ I am sorry Daniel. I am too new to the forum. Have hardly become active. I will take care next time. Thanks for your valuable suggestion / warning. $\endgroup$ Commented May 9, 2016 at 15:20
  • $\begingroup$ I am deleting this Answer as this has been marked no worth as an answer. Thank You Daniel. I have added the answer in the comment above. $\endgroup$ Commented Jun 1, 2016 at 5:18
  • $\begingroup$ I don't have the permission to delete this answer....? What to do. $\endgroup$ Commented Jun 1, 2016 at 5:18

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