I'm trying to make sense of this logarithm, any tips on how to handle the $\log _{x^2}$ part is appreciated.
Solve the equation and find the largest (real) solution. $\log_ x(3-x) = \log_{x^2}(8-3x-x^2)$.
I tried squaring the right hand side to get rid of the $x^2$ term and have the same base on both sides but the squaring gives a rather complicated polynomial which doesn't make much sense.