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Does the following series converge, does it converge absolutely? $$\sum_{n=1}^\infty \frac{n+2}{n^2+4n-7}\left(\frac{4}{7}\right)^n $$

Now I thought about using Dirichlets Test of Uniform Convergence.

I know that $|\sum_{n=1}^\infty (\frac{4}{7})^n|\leq M < \infty$.

I am left to show that if $\frac{n+2}{n^2+4n-7} \rightarrow 0$ uniformly then my whole series converge uniformly?

What does uniform convergence of series mean?

I know that it means partial summs converge uniformly, but what is it in lazy mans terms? Does it imply absolute convergence?

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  • $\begingroup$ This problem will succumb to a simple Comparison Test. Give it a try. $\endgroup$
    – hardmath
    May 8, 2016 at 18:07
  • $\begingroup$ It will be easier the other way around, $\forall n \geq 2, \frac{n+2}{n^2+4n-7} \leq 1$. Then use the convergence of $\sum_{n = 1}^N (\frac{4}{7})^n$ $\endgroup$
    – Vincent
    May 8, 2016 at 18:12
  • $\begingroup$ Root test is also good. $\endgroup$
    – Slowpoke
    May 8, 2016 at 18:13

2 Answers 2

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Hint. One may just observe that $$0\leq \sum_{n=2}^\infty \frac{n+2}{n^2+4n-7}\left(\frac{4}{7}\right)^n\leq \sum_{n=2}^\infty \left(\frac{4}{7}\right)^n<\infty. $$

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hint: $\dfrac{n+2}{n^2+4n-7} < 1 (n \geq 3) $ and $\left|\dfrac{4}{7}\right| < 1$

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