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$$a^{bx} = c$$

Solve for x

$$\log a^{bx} = \log c$$

$$bx \log a = \log c$$

$$x = \frac{\log c}{b \log a}$$

Is this correct?

Thanks :)

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  • $\begingroup$ Yes, it is correct. I am assuming that $a$ is positive. $\endgroup$ Commented May 8, 2016 at 5:15
  • $\begingroup$ What are the ranges of the parameters and the variable? $\endgroup$
    – joriki
    Commented May 8, 2016 at 5:32
  • $\begingroup$ @joriki: Ranges aren't mentioned in the question $\endgroup$
    – Zantheor
    Commented May 8, 2016 at 5:40
  • $\begingroup$ @Andre: thanks! $\endgroup$
    – Zantheor
    Commented May 8, 2016 at 5:41
  • $\begingroup$ You are welcome. $\endgroup$ Commented May 8, 2016 at 5:41

1 Answer 1

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Community wiki answer so the question can be marked as answered:

No ranges are given. As André noted in a comment, some assumptions are required. If $a$ is assumed to be a positive real number, your calculation is correct.

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