Evaluate the integral $$\int x^7\cos(x^4)\,dx$$
I first tried integration by parts with $u = \cos(x^4)$, $du = -4x^3(\sin(x^4))$ $dv = x^7$ and $v = \frac 18 x^8$ which gave me
$$ \frac 18x^8\cos(x^4) - \int-4x^3\sin(x^4)\cdot\frac18x^8$$
I tried to solve the second integral using integration by parts, first plugging in $u = \frac 18x^8$ and $dv = -4x^3\sin(x^4)$. I discovered this doesn't work. I thought about other options for $u$ and $dv$ but it seemed like they would only yield more complicated equations, is there something I'm missing here? Can anyone guide me through the next step?