0
$\begingroup$

This question already has an answer here:

I'm solving few math puzzles to train myself for a local math contest, and I'm stuck with this problem :

Compute the sum of :

$$\frac{1}{2*1} + \frac{1}{2*3} + \frac{1}{3*4} + ... + \frac{1}{2013*2014}$$

As said in the title, I know that all of those, can be written as : $\frac{1}{n(n+1)}$

But the $n(n+1)$ is not a geo seq nor an arithmetic one . So there are no theorems to compute their sum .

I'v also found a good number of similar puzzles so how can I solve this kind of problems ?

$\endgroup$

marked as duplicate by Workaholic, Alex M., Ethan Bolker, user147263, Shailesh May 12 '16 at 0:04

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

1
$\begingroup$

The $\frac{1}{n(n+1)} $ is called a telescopic sum, which telescopically can be expressed as : $\frac{1}{n(n+1)} = \frac{1}{n} - \frac{1}{n+1}$, which simplifies your initial expression. (This is the way that you express the series sum too).

$\endgroup$

Not the answer you're looking for? Browse other questions tagged or ask your own question.