# Independent and joint probability?

I got this question from my statistics teacher, but his answer made me confused. The question is this..

Given that A, B and C are three independent events such that P (A)=0.2 ,P(B)=0.6 ,P (C)=0.5, then the joint probability for the three events is:

a) 0.751 b) 0.06 c) 0.500 d) 0

My teacher said that "d" is the correct answer. However I believe that "b" is more reasonable answer, because the events are independent and also joint (not mutually exclusive). So what do you think?

• independent leads to the product $0.06$, which mutually exclusive is not possible when the sum is greater than $1$ – Henry May 6 '16 at 13:05
• Who is a statistics doctor? – Aman May 6 '16 at 13:12
• The statistics doctor is the one who holds the cure for OP's teacher. – jdods May 6 '16 at 14:45
• You don't need to say "joint" to assure "not mutually exclusive". If two events, P and Q, ARE mutually exclusive then the probability of "P given Q" or "Q given P" is 0 so they are not "independent". Any independent events are automatically "not mutually exclusive". – user247327 May 6 '16 at 14:57