# Is it known if $\frac{\zeta(3)}{\pi^3}\in\mathbb{Q}$? [duplicate]

Is it known if $\frac{\zeta(3)}{\pi^3}\in\mathbb{Q}$?

It is obvious that $\frac{\zeta(2n)}{\pi^{2n}}\in\mathbb{Q}$, but since there is no closed form for the odd values, are we left to be unable to determine if the solution could have such a form?

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• mathoverflow.net/questions/60595/is-zeta3-pi3-rational – Wojowu May 5 '16 at 11:46
• @Wojowu Thanks. – Simply Beautiful Art May 5 '16 at 11:47
• I'm not sure it is that "obvious" that $\frac{\zeta(2n)}{\pi^{2n}}\in\mathbb{Q}$... – fretty May 5 '16 at 12:14
• @fretty Did you look at the general solution to $\zeta(2n)$? Every component with the exception of the $\pi^{2n}$ is rational, and multiplied and divided together, ${\mathbb{Q}\over\mathbb{Q}}\in\mathbb{Q}$ – Simply Beautiful Art May 5 '16 at 20:54
• But the formula itself is hardly obvious... – fretty May 5 '16 at 22:29

Well $\zeta(3)$ is what known as Apery's constant, and it is proved to be irrational. But whether $\frac{\zeta(3)}{\pi^3}$ is rational or not is not known. For little more info you can check this link