If the circle
$$x^2 + y^2 + 2gx + 2fy + c = 0$$
cuts the three circles
$$x^2 + y^2 – 5 = 0\space;\space x^2 + y^2 – 8x – 6y + 10 = 0 \space;\space x^2 + y^2 – 4x + 2y – 2 = 0;$$ at the extremities of their diameters, then
(A) $c = – 5 $
(B) $fg = 147/25$
(C) $g + 2f = c + 2 $
(D) $4f = 3g$
I'm not understanding a single thing. Please Help