i am confused by the sine of an angle, (it might appear evident for some of you but please i am not an expert ). sine of an angle is says to be the half of the magnitude of the chord of 2 time the angle.geometrically, it is just the opposite edge of a right triangle. so if one do not associate a circle , one angle will have infinite sine. then why the formula soh cah toa is still applicable since it imply the use of two circles(each of the similar right triangles)? considering this representation ,
depend on the circle , sin Â = BC or sin Â = B'C'. how can sin Â be (B'C')/(AB')?
thank in advance, i will be happy to reformulate the question if there is an unclear point