Let $G$ be a finite group and $S$ a finite set of prime numbers. I know that every separable $\mathbb Q$-algebra $A$ contains a maximal $\mathbb Z$-order but I wonder if the following is true.
Is there a $\mathbb Z$-order $\Lambda$ in $\mathbb Q[G]$ which contains $\mathbb Z[G]$ and is such that $\Lambda\otimes_\mathbb Z \mathbb Z_p$ is a maximal $\mathbb Z_p$-order in $\mathbb Q_p[G]$ if $p\in S$ and also $\Lambda\otimes_\mathbb Z \mathbb Z_p=\mathbb Z_p[G]$ if $p\notin S$?
Here $\mathbb Q_p$ (resp. $\mathbb Z_p$) is the $p$-adic completion of $\mathbb Q$ (resp. $\mathbb Z$).
Thank you for your help.