A loan of $10,000$ is being repaid with 20 non-level annual payments. The interest rate on the loan is an annual effective rate of$6$% . The loan was originated 4 years ago. Payments of $500$ at the end of the first year, $750$ at the end of the second year, $1000$ at the end of the third year, $1250$ at the end of the forth year have been paid.

Calculate the outstanding balance immediately after the forth payment.

I tried through

Present value of all payments = Amount of Loan

$\frac{500}{1.06} +\frac{750}{1.06^2}+\frac{1000}{1.06^3}+\frac{1250}{1.06^4}+B_{(4)}^r=1000$

Getting some problems here. This equation does not fit in.

  • $\begingroup$ That's simply not how compound interest works. $\endgroup$
    – user21820
    Commented Apr 17, 2016 at 8:00

1 Answer 1


After first year, the balance is 10000*1.06-500=10100. After the second year, the balance is 10100*1.06-750=9956. After the third year, the balance is 9956*1.06-1000=9553.36. After the 4th year, 8876.5616. In general, for $P_i$ payments at the end of year $i$, the balance is $$B^r_{(n)}=10000 \times 1.06^n-\sum_{i=1}^n P_i\times1.06^{n-i}$$


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