Solve integral equation using Laplace transform and convolution

Solve $$y(x)=e^x(1+\int_{0}^{x}e^{-t}y(t) dt)$$

Here's what I did: take derivative on both sides, $y'(x)=e^x+e^x \int_{0}^{x}e^{-t}y(t)dt +e^xe^{-x}y(x) \Rightarrow y'(x)=e^x+y(x)-e^x+y(x) \Rightarrow y'=2y$. Hence the solution looks like $y(x)=e^{2x}+C$. But I wonder how to solve this equation using Laplace transform and convolution. Any idea?

Your equation can be written as: $$y(x) = e^{x} + \int_{0}^{x} e^{x-t}y(t)dt = \exp(x) + [\exp*y](x).$$ Then, if $Y(s)$ is the Laplace transform of $y(x)$, you get $$Y(s) = \dfrac{1}{s-1} + \dfrac{ Y(s) }{s-1} \implies Y(s)=\dfrac{1}{s-2}$$ which means $y(x) = e^{2x}$.