How can an absolute value equation with a variable have both a positive, and negative answer? I thought absolute values are supposed to be a number's distance from 0, which is always positive. So I had this equation:

| 7 – y | = 12

According to practice tests they say this,

This equation means we need to solve two equations: 7–y=12, and 7–y=-12 which means y=-5,19.

Even if the answer inside the vertical bars was negative, wouldn't the vertical bars make it positive, resulting in just 1 positive answer?
Thanks for any help you can give!
Edit
I found out what happened! I didn't notice when they said the equations could have both 12, and -12 they didn't include absolute value bars, so they were just referring to how the variable can be both positive, or negative.
 A: Not quite.
Recall that
$$|y| = \begin{cases}y,&\text{if } y\geq 0\\-y,&\text{if } y<0\end{cases}$$
Notice that the problem asks for all values $y$ such that 
$$|7-y| = 12.\tag 1$$
If $y = -5$, then
$$|7-(-5)| = |7+5| = |12| = 12.$$
Further, if $y = 19$, then
$$|7-(19)| = |-12| = -(-12) = 12$$
using  the rule above.
Hence the values of $y$ that satisfy equation $(1)$ are $-5$ and $19$.
So although $y = 19$ gives $|-12|$, it still satisfies equation $(1)$ since we take the absolute value: since $-12<0$, we have that $|-12| = -(-12) = 12.$
A: $7-y=12$ or $7-y=-12$
$y=-5$ or $y=19$
If $y=-5$ then $|7-(-5)|=|12|=12$ and if $y=19$, then $|7-19|=|-12|=12$
A: $|7-y|=12$ means that the distance (as you point out, this distance can only be nonnegative) between 7 and y is 12. Now, in $\mathbb{R}$ (the space of real numbers), there are two values of $y$ that are 12 units distant from 7. One of them is 12 + 7 = 19, while the other is -12 + 7 = -5.
Even though you have not asked for this in your OP, if we are talking about points in $\mathbb{R}^2$ and consider the "7" to be (7,0), the equation corresponds to the points on a circle centered at (7,0) with radius 12. In this case, there will be infinite number of solutions to this equation.
A: 
Even if the answer inside the vertical bars was negative, wouldn't the vertical bars make it positive, resulting in just 1 positive answer?

The vertical bars are there to express a property you want your $y$ to have. They don't influence what $y$ itself is.
A solution to the equation means the value of the $y$ you start your computation with, before subtracting it from $7$ and positivising the result. Both of those things happen during the calculation you want to work, but doing them doesn't change the fact that the $y$ you started out with might have been $-5$.
