# Drawing cards without replacement: all kings before any jacks

This is a question that came up with my friends while playing a card drinking game:

You draw cards without replacement from a standard 52-card shuffled deck. What is the probability that you draw all of the kings before drawing any of the jacks?

I was thinking of a solution along the lines of combinations, but I'm not sure if that's the way to go. Simulation tells me the answer is ~1.4%, but I don't know how to get to this answer.

Disclaimer: This is not a homework question. I'm really just curious.

• You should never drink while playing cards. – wolfies Apr 11 '16 at 14:23

There are $\binom{8}{4}$ equally likely ways to choose the places occupied by the Kings. Only one of these is "favourable."
Thus the probability that all the Kings come before any Jack is $\dfrac{1}{\binom{8}{4}}$. This is approximately $0.0143$, quite close to the number obtained in the simulation.