Suppose we have a standard well shuffled $52$ card deck and deal cards from it without replacement (for each hand). Which is likely to happen first on average, we deal out an entire suit (all $13$ cards of any one suit) or get $3$ quads?
None of the cards have to be in any special order, just that they show up. For example, the quads could show up with other "irrelevant" cards in between.
Note that both of these are stopping conditions for a trial, whether you first get the full suit or the triple quads.
Also note that each case could be poised, waiting for $1$ card to "win" but a single card drawn could satisfy both conditions simultaneously and thus will be considered a tie or no decision and we would then reshuffle and retry a new hand. For example, if you needed the K of hearts to complete all $13$ hearts but you also have seen $5,5,5,5,3,3,3,3,K,K,K$ so far with no other quads seen yet that hand. The K of hearts would satisfy both conditions simultaneously and thus create a "tie" (no decision) situation, prompting a reshuffle and retrial.