I need some help understanding how to proceed for the inverse tranform of the following function:
$X(f)=\frac{1}{2} sinc(f-f_0)+\frac{1}{2} sinc(f+f_0)$
Any help would be much appreciated.
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$\begingroup$ It looks very straightforward if you have a table of Fourier Transforms under the eyes. What have you tried yet ? $\endgroup$– Jean MarieApr 4, 2016 at 22:55
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1 Answer
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$$f(t)\cos(2 \pi f_0t) \Longleftrightarrow \frac{1}{2}[F(f - f_0) + F(f + f_0)]$$
$$\text{rect}(t) \Longleftrightarrow \text{sinc} (f)$$
