# Polynomial degree [closed]

Consider this equation: $9(x-0.4)^4+2$. I just want to confirm that this is a 4th degree polynomial.

## closed as off-topic by Adam Hughes, Claude Leibovici, Watson, S.C.B., colormegoneApr 4 '16 at 7:18

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• What leads you to think that it is or that it isn't? – Eric Towers Apr 4 '16 at 5:20
• I am about 98% sure that it would be a 4th degree polynomial because it is raised to the 4th power. I just didn't know if the parentheses would change anything. – user328399 Apr 4 '16 at 5:23
• The binomial theorem guarantees that the parentheses do not change anything. The degree of $(a+x)^n$ is $n$. – Wouter Apr 4 '16 at 5:32

We can just do it by brute force: $$9\left(x-\frac{2}{5}\right)^4 + 2 = 9x^4 - \frac{72}{5}x^3 + \frac{216}{25}x^2 - \frac{288}{125}x + \frac{1394}{625}$$ or, you can notice that raising a polynomial of order $m$ to exponent $n$ yields a polynomial of degree $mn$. It can be shown rigorously using the Binomial Theorem.

Yes , degree of a polynomial is the highest degree of its terms. In this case, it is indeed 4

Yes, it is. In general, a function of the form

$f(x) = a(x-b)^n + c$ where $n\geq1$ and $a \neq 0$ is a polynomial of degree $n$. This can be verified with the binomial theorem.

• Thank you. And coefficients would be -0.4 and 2, right? – user328399 Apr 4 '16 at 5:24
• @user328399 No. The leading coefficient would be $9$ – MathematicsStudent1122 Apr 4 '16 at 5:26
• I meant to say constant, sorry mate. But, -0.4 isn't a constant? – user328399 Apr 4 '16 at 5:27
• @user328399 No, the constant would be something else. Try expanding it for youself! – MathematicsStudent1122 Apr 4 '16 at 5:29
• @MathematicsStudent1122 I think OP is asking if in their case $a=9$, $b=0.4$, $c=2$, in which case they're correct – leibnewtz Apr 4 '16 at 5:32