# What curve is traced out by the vertex of the parabola $ax^2+bx+c$ as $b$ varies?

Consider the parabola $$\rho$$ given be the equation $$y = ax^2 + bx + c$$. Recall that varying $$a$$ in this equation stretches/squashes $$\rho$$ and that varying $$c$$ shifts $$\rho$$ vertically. The change in the parabola $$\rho$$ as you vary the value of $$b$$ is a bit harder to describe, but as you vary $$b$$, the vertex of $$\rho$$ traces out a familiar curve. What is this curve? What it the equation of this curve?

First let's write down the general form for the vertex of $\rho$. Through any of various means we can find that the $x$-coordinate of the vertex is $-\frac{b}{2a}$. Substituting this value into the equation for $\rho$ we get that the vertex is
$$\left(-\frac{b}{2a},\;\; c-\frac{b^2}{4a}\right).$$
Since the $x$-coordinate of the vertex is linear in $b$ and the $y$-coordinate is quadratic in $b$ (has a $b^2$), we can conclude that the vertex of $\rho$ traces out a parabola. We can reparametrize this curve to get an explicit equation to describe it. Letting $t = -\frac{b}{2a}$ we can make the substitution $b = -2at$ into the $y$-coordinate, giving us the parametric curve defined by
$$\left(t,\;\; c-\frac{(-2at)^2}{4a}\right) \;\;=\;\; \left(t,\;\; c-at^2\right) .$$
To state this explicitly, the curve traced by the vertex of $\rho$ is given by the equation $y = c - ax^2$.