# Evaluating right hand limit for a function

I want to prove the following right-hand limit (one sided limit) using $\epsilon-\delta$ definition;

$\lim_{u\to 0^+} {u^{s_0} f(-ln u)} = 0$

where $f$ is a function from $R \to R$ and $s_0$ is a positive real number.

Can anybody assist me in it.

I searched out its proof or any hint, in this forum, but could not find it.

• It may be an easy question, but I have not any clue about its proof. Can anybody run me with some proof steps... – A.A Mar 31 '16 at 7:15
• What is $f$ ? .. – Zanzi Mar 31 '16 at 7:34
• $f$ is any function from $R \to R$. Let me edit question please. – A.A Mar 31 '16 at 7:45
• The existence of the limit depends on $f$ and $s_0$... With these information, nothing can be said. – Crostul Mar 31 '16 at 8:08
• I have added the information about $s_0$ i the question. – A.A Mar 31 '16 at 8:24