$P(A \cup B)=P(A)+P(B)−P(A \cap B)$
I found the following numbers, and verified that they are indeed correct:
$P(A) = 0.2$, $P(B) = 0.3$, $P(A \cup B) = 0.5$, $P(A \cap B) = 0$(Mutually exclusive), $P(C) = ?$
The thing is, there is no $P(C)$ in the additive principle, I found all of these values, but I'm not sure how I can fit $P(C)$ into the principle, if $P(C)$ doesn't exist in the first place. If someone can just push me in the direction that'd be awesome!
Entire question BELOW.
A sample space contains only three simple events: A, B, and C. If P(A) = 0.2 and P(B) = 0.3 find:
P(A and B) if A and B are mutually exclusive
P(A or B) if a and B are mutually exclusive
P(C) if A and B are mutually exclusive