# determine the centre points of the circle

Given:

• Circle with centre $M (-5; 5)$
• The equation is $(x+5)^2 + (y-5)^2 = 50$

Suppose this figure is translated $6$ units to the right and $3$ units down. What is the new centre of the circle?

My attempt for the centre is $x + 6$ and $y - 3$, yielding $M (1; 2)$, but the answer in the textbook is $M (1; 5)$

Explain?

• Explain? Typo. 6 units to the right of -5 is 1. 3 units down from 5 is 2 so the center is (1,2). That's it. Unambiguous and inarguable. The book is wrong. I don't the book author is stupid so ... I must conclude it is an uncaught typo. – fleablood Mar 22 '16 at 17:15

The equation implies the circle center at $(-5,5)$ indeed, which is your point $M$. Moving 6 right and 3 down should yield $$(-5,5) + (6,-3) = (-5+6,5-3) = (1,2)$$