Can anyone share an easy way to approximate $\log_2(x)$, given $x$ is between $0$ and 1?
I'm trying to solve this using an old fashioned calculator (i.e. no logs)
EDIT: I realize that I stepped a bit ahead. The x comes in the form of a fraction, e.g. 3/8, which is indeed between 0 and 1, but could also be written as log2(3) - log2(8). I am hoping there is a quick way to approximate this calculation to let's say 2 decimals