"does anyone know how i can find the radius of circle 1 and circle 2?"
Circle 1. The vertices of the square are in the circle. That's what "circumscribe" means. The diagonals of a square bisect each other so the distance from the center of the square to each of the vertices are equal distance. That's four points on a circle each equal distance from a central point.
A little bit of futzing and one can prove given three or more points on a circle there is only one point (namely the center of the circle) and only one distance (the radius) that is equal distance from all the three or more points on the circle.
So the radius of Circle 1 is half the diagonal of the square.
Circle 2. Each side of the square is tangent to smaller circle 2. A bit of futzing and one can prove the perpendiculars of tangents to a circle all intersect in the center of the circle. So the four perpendiculars intersect at the center of the circle. As opposite sides of a square are parrallel it follows these tangents must occur in the midpoints of the sides (otherwise the perpendiculars from the opposite sides wouldn't intersect.)
So the radius of Circle 2 are the lines from the center of the square to the midpoints of the sides of the square.
So the radius of Circle 2 is half the side the square.