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Suppose $f:\mathbb{R}\rightarrow\mathbb{C}$. We'd like to take the Fourier Transform of this function, defined as $$F(s) = \int_{-\infty}^\infty f(x)e^{-i \, 2\pi \, s \, x}dx.$$ However, a computer can't do this in general. Instead, we "sample" the function and then compute the Discrete Fourier Transform. Sampling is modeled as multiplication with a comb function $\text{III}(x)=\sum_{n=-\infty}^\infty\delta(x-n)$.

So we take the Fourier Transform of $f\,\text{III}$.

At this point I'm confused about a few things.

1) Shouldn't we model sampling as multiplication with a comb and a rect function like this: $f\,\text{III}\,\Pi_\Delta$ where $$\Pi_\Delta(x)=\left\{\begin{array}{ll}1 & \text{ if } |x|/\Delta < 0.5\\0 & \text{otherwise}\end{array}\right..$$ Don't we need this in order to account for the fact that we have a finite number of samples?

2) How does the Fourier Transform of $f\,\text{III}$ relate to the Discrete Fourier Transform of the samples?

Thank you.

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  • $\begingroup$ You can use $Ш$ for Dirac comb. $\endgroup$ – Henricus V. Mar 17 '16 at 5:26
  • $\begingroup$ @HenryW. I would LOVE to! I can't seem to edit your post and view the latex. What's the latex for that symbol? $\endgroup$ – NicNic8 Mar 17 '16 at 5:32
  • $\begingroup$ It is a Cyrillic letter by itself: Ш Related:tex.stackexchange.com/questions/124738/… $\endgroup$ – Henricus V. Mar 17 '16 at 5:33

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