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I understand the basics of the $W$ Lambert function, but I have problems working out some problems with it. I know the answer, but I don't know how to derive it. Help would be appreciated. $y^y=x$ is the same as $y=\log(x)/W(\log(x))$

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  • $\begingroup$ Get it into the form $g(x)=f(y)e^{f(y)}\implies f(y)=W(g(x))\implies y=f^{-1}(W(g(x)))$ $\endgroup$ – Simply Beautiful Art Mar 17 '16 at 12:10
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We have \begin{align*} x &= y^y \\ \iff \log x &= y \log y \tag+\\ \iff \log x &= \log y \exp(\log y)\\ \iff W(\log x) &= \log y\\ \iff W(\log x) &= \frac{\log x}y & \text{by $(+)$}\\ \iff y &= \frac{\log x}{W(\log x)} \end{align*}

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