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$\frac{2d^2-d-10}{d^2+7d+10} = \frac{d^2-4d+3}{d^2+2d-15}$

What is the optimal solution for finding the value of d?

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    $\begingroup$ Both quadratics on the left factor, and have a common factor. Are you sure you entered the formulas correctly on the right-hand side? $\endgroup$ – rogerl Mar 16 '16 at 20:42
  • $\begingroup$ @rogerl Sorry! My mistake, I typed a + instead of a - $\endgroup$ – Juanvulcano Mar 16 '16 at 20:44
  • $\begingroup$ Well, now you can factor both quadratics on the right as well, and they have a common factor. That should make things much easier. $\endgroup$ – rogerl Mar 16 '16 at 20:45
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Factor the quadratics. You can pull out $x+5$ on the left and $x-3$ on the right.

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Your expression can be written as

$$ \frac{(2d-5)(d+2)}{(d+5)(d+2)} = \frac{(d-1)(d-3)}{(d+5)(d-3)}.$$

Can you see how to proceed from here?

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