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The following question was asked during the final exam of AISSCE. Evaluate $\int_{-2}^2 \frac{x^2}{1 + 5^x}dx$. I think it must be easy and leave it to wide audience to check...cheers!


marked as duplicate by GoodDeeds, Martin Sleziak, gebruiker, user1551, Alex Provost Mar 16 '16 at 22:19

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  • $\begingroup$ Hint: substitute $x \to -x$ and consider the sum of the new and the original integral. $\endgroup$ – StackTD Mar 16 '16 at 11:31

Note that $\int_{-2}^2\frac{x^2}{1+5^x}dx=\int_{0}^2\frac{x^2}{1+5^x}dx+\int_{-2}^0\frac{x^2}{1+5^x}dx$. Taking $u=-x$ in the second integral, we have



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