The perimeter of a basketball court is 72m. The difference between its length and its width is 12m. Solve the system to determine the dimensions of the court. I keep getting different answerers and can't seem to find the right on. Please help.
Your question give us the information we need to make two equations.
First: $2l + 2w = 72$. This shows that the perimeter is 72 m.
Second: $l - w = 12$. This shows that the difference between its length and width is 12m.
Now we have to solve these equations. We can rearrange (2) to get $l = 12 + w$. We then substitute that into (1) and get $2(12 + w) + 2w = 72$. We can simplify that to get $24 + 4w = 72$. If we solve for $w$ we get $w = 12$. Now we need to find $l$. Just put $w$ into $l = 12 + w$ and we get $l = 24$.
I hope this helps. You should try asking your teacher with this kind of question. It's their job to help you.