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A simple question, just for clarifying: suppose we have two riemannian metrics $g$ and $\tilde{g}$ in a differentiable manifold $M$, and assume they are conformal say, with $\tilde{g} = \mu g$ for some positive valued differentiable function $\mu : M \to \mathbb{R}$. This means that

$$\tilde{g}(p)(v, w) = \mu(p) g(p)(v, w), \quad \forall p \in M, \forall v,w \in T_p M$$

right?

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    $\begingroup$ Yes, but do write $g(p)(v,w)$ as well. $\endgroup$
    – John B
    Commented Mar 1, 2016 at 1:12
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    $\begingroup$ Yes, forgot that :) $\endgroup$ Commented Mar 1, 2016 at 1:14

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Yes indeed! Your definition is correct.

Just to add a little meat ... the intuition here is that the function $\mu$ tells you how much the scale in each tangent space changes. If $\mu$ is large at $p$, then a circle of radius $1$ with respect to $g$ has large radius with respect to $\widetilde{g}$, and if $\mu$ is small, then a circle of radius $1$ with respect to $g$ has correspondingly small radius with respect to $\widetilde{g}$.

Note, however, that circles are still circles. The only difference is pointwise volume; angles remain the same.

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