Hypotheis Testing (paired T test): 1) Is my work correct? 2) How to graph in SPSS,? I have the following Hypotheis testing problem.
The statement of the exercise is:

Experiment: Eleven different varieties of barley were considered. Of
  each variety, half was kiln-dried and the other half was left
  untreated. Then the two batches of seed were sown in adjacent plots.
  The experimenter observed that kiln-dried seeds gave, on average, the
  larger yield of kernels and straw but the quality was generally
  inferior. The data set “KilnDriedBarley.txt” contains data on the year
  of the planting, and the value of the crop (in shillings per acre) for
  both kiln-dried and non-kiln-dried seeds. Seeds sown on adjacent plots
  are listed in the same row of the file.

 Year   NonKilnDried    KilnDried

1899       140.5            152
1899       152.5            145
1899       158.5            161
1899       204.5            199.5
1899         162            164
1899         142            139.5
1899         168            155
1900         118            117.5
1900       128.5            121
1900       109.5            116.5
1900       120              120.5


(i) “Does kiln-drying barley seeds increase the average value of the
  crop?” Should we use an independent sample or a paired sample test to
  answer this question? Defend your choice.

My answer: For this experiment we need to use t test paried sample, because it is assumed that each of the eleven types of seed will have the same condition to growth execect the parameter we want to study, in this case is kiln-dried seed and non-klin dried seeds.

(ii) Use SPSS to create an appropriate graphical display of your data.
  Your graph should show how the kiln-drying affects crop value.
  Describe what you can see in the graph.

I need help in this part, because I have no idea how to display my data in SPSS showing my data and the test. 

Part (iii) Conduct a statistical hypothesis test for the question in
  (i) at significance level $\alpha = 0.05.$ Include relevant SPSS output.
  Formulate a conclusion for the test and cite the appropriate p-value.

This is my output:

My answer: The P-value is .602. We have not enough evidence to reject $H_0$ in favor of $H_a.$ Therefore there isn’t any significance differences between the average value of the crop with kiln-drying barley seeds at a significance level of ($\alpha=5\%$).
Overall question:
1) Are my assumption, and conclusion correct for this experiment? 
     I notice also that both samples has very similar sample std. therefore I assumed homoscedastic (anyway is computed by SPSS).
2) The second problem I have is that I want to use spss, but I can't find an option to graph the t test. (I belive is that what the question ii asked for).
Thank you for your help. 
 A: You are correct that this is a paired model and that (assuming
nearly normal data) you can use a paired t test to judge whether the population mean differences (between kiln dried and non-kiln) are consistent with 0 ($H_0$) or not ($H_a$). 
Using SPSS, you have
found no significant difference between kiln dried and not (P-value 0.6). In addition a 95% CI for the population difference $\delta = \mu_n - \mu_k$ includes 0, indicating that the data are consistent
with no difference.
I repeated the test using Minitab. (I do not have ready access to 
SPSS.) Here is the output:
 Paired T-Test and CI: NonK, Kiln 

 Paired T for NonK - Kiln

              N    Mean  StDev  SE Mean
 NonK        11  145.82  27.40     8.26
 Kiln        11  144.68  25.51     7.69
 Difference  11    1.14   7.00     2.11


 95% CI for mean difference: (-3.57, 5.84)
 T-Test of mean difference = 0 (vs not = 0): 
    T-Value = 0.54  P-Value = 0.602

Lacking access to SPSS, I cannot show you how to use SPSS to make an
appropriate graph, but I can tell you what I think the
author of the question is looking for. 
First, you should
find the eleven differences. They are: 
 11.5, -7.5, 2.5, -5.0, 2.0, -2.5, -13.0, -0.5, -7.5,  7.0,  0.5

[Note: A paired t test is equivalent to a one-sample t test on
the differences (testing the null hypothesis of null difference
against the two-sided alternative). Because of the paired nature
of the data it would be inappropriate to do a two-sample t test. (Kiln dried and Not are $correlated$, not independent.)
Accordingly, it would be inappropriate to compare two separate
plots for Kiln dried and Not.]
Then you can make a dotplot (stripchart), boxplot, or histogram
of the differences. Look in the SPSS menus to find out what
kinds of graphs are available. A Minitab dotplot in typewriter text format
is shown below:
         .          :    .    .   . .  ..        .        .
     +---------+---------+---------+---------+---------+-------Dif
 -15.0     -10.0      -5.0       0.0       5.0      10.0

Plots below show a boxplot and a histogram. Each statistical
package has its own style of plots, so your plots in SPSS may
look a little different, but none of them should give a visual
impression that the mean difference is significantly different 
from 0. In my opinion, eleven is getting near the lower limit of the sample
size for which a boxplot is an effective graphical display,
and perhaps eleven really is too small for a nice histogram. So I
would prefer something like Minitab's 'dotplot' or a 'stripchart' from
R shown last. These graphical displays show the locations of
each individual difference.



