Chevalier de Méré knew that probability of rolling six with a six-sided die is $\frac 16$. He reasoned that his chance to roll six with 4 tries is $\frac 46$, which is not the case. It is $1 - (\frac 56)^4$.
Which event's probability was calculated then? That is, which event has probability of $\frac 46$ in an experiment of throwing a six-sided die four times?